数学理

2025-05-16 0 0 395.76KB 9 页 10玖币
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数学(理科)评分标准 第 1 页 共
9
绵阳市高中 2021 级第三次诊断性考试
理科数学参考答案及评分意见
一、选择题:本大题共 12 小题,每小题 5分,共 60 分.
CBACB DDCBC DA
二、填空题:本大题共 4小题,每小题 5分,共 20 分.
1310 14
15
162
三、解答题:本大题共 6小题,共 70 分.
17:(1)由列联表可计算 ,·······4
∴有 95%的把握认为参数调试能够改变产品合格率.···························5
2)根据题意,设备更新后的合格概率为 0.8,淘汰品概率为 0.2········6
可以认为从生产线中抽出的 6件产品是否合格是相互独立的,················8
X表示这 6件产品中淘汰品的件数,则 ,·······················9
可得: ································10
·····················································12
18:(1)设 的公差为 d,则 11+d2+2d成等比数列,················1
∴ ,解得:d=1 d=−1·····································3
d=−1,不满足 , 成等比数列,
d=1······················································································4
数列 的通项公式
······················································5
2)令 ,·····························6
∴ ,······················7
两式相减有: ,
··················8
∴数列 的前 n+1 项和为 ,即 ·······························9
,所以 ,························································10
····················································11
数学(理科)评分标准 第 2 页 共
9
∴ .···········································································12
19:(1)过 CCH⊥交于H···········································1
∵ 在平面 内的射影落在棱 上,
平面 ,又 平面 ,···································2
∴ ,·············································································3
又 ,且 ····················································4
∴ 平面 ··································································5
2)∵ ,则 ,·························6
C ,连结
AA1CC1的距离为
又∵ 平面 ,则 ···········································7
RtCHQ 中: ,则 ,
且 ,
平面
又由1)知: 平面 ,∴
,则四边形 ABHQ 为矩形,
又四边形 ABB1A1的面积为 3,则 BB1=3···········································8
为 轴
空间直角坐标系
, ,
解得 ,············································9
B(200) , ,
, ,
摘要:

数学(理科)评分标准第1页共9页绵阳市高中2021级第三次诊断性考试理科数学参考答案及评分意见一、选择题:本大题共12小题,每小题5分,共60分.CBACBDDCBCDA二、填空题:本大题共4小题,每小题5分,共20分.13.1014.15.16.2三、解答题:本大题共6小题,共70分.17.解:(1)由列联表可计算,·······4分∴有95%的把握认为参数调试能够改变产品合格率.···························5分(2)根据题意,设备更新后的合格概率为0.8,淘汰品概率为0.2.········6分可以认为从生产线中抽出的6件产品是否合格是相互独立的,········...

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