ASYMPTOTICS OF THE MAJOR INDEX OF A RANDOM STANDARD TABLEAU PIERRE-LOÏC MÉLIOT AND ASHKAN NIKEGHBALI

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ASYMPTOTICS OF THE MAJOR INDEX
OF A RANDOM STANDARD TABLEAU
PIERRE-LOÏC MÉLIOT AND ASHKAN NIKEGHBALI
Abstract. In this article, we establish the mod-φconvergence of the major index of a uniform
random standard tableau whose shape converges in the Thoma simplex. This implies various
probabilistic estimates, in particular speed of convergence estimates of Berry–Esseen type, and
strong large deviation principles.
Contents
1. Major index of a random standard tableau 2
1.1. Integer partitions and standard tableaux 2
1.2. Major index and Schur functions 3
1.3. Cumulants of the major index 4
1.4. Growing partitions and the Thoma simplex 7
1.5. Main results and outline of the paper 9
2. Observables of integer partitions 13
2.1. Cumulants and the Kerov–Olshanski algebra 13
2.2. Descents and Frobenius moments 16
2.3. Symmetric functions of the contents 18
2.4. Asymptotics of the cumulants 24
3. Asymptotics of the distribution of maj(T)25
3.1. Asymptotics of the log-Laplace transform 25
3.2. Upper bounds on cumulants and Berry–Esseen estimates 27
3.3. Exponential tilting of measures and control of the tilted Fourier transforms 29
References 35
Date: October 25, 2022.
1
arXiv:2210.13022v1 [math.PR] 24 Oct 2022
2 PIERRE-LOÏC MÉLIOT AND ASHKAN NIKEGHBALI
1. Major index of a random standard tableau
1.1. Integer partitions and standard tableaux. If λ= (λ1λ2≥ ··· ≥ λ`(λ))is a non-
increasing sequence of positive integers, we recall that it is called integer partition of the integer
n=|λ|=P`(λ)
i=1 λi, and that it is represented by a Young diagram, which is the array of n
boxes with λ1boxes on the first row, λ2boxes on the second row, and so on. For instance, the
integer partition λ= (4,2,2,1) has size |λ|= 9, and it is represented by the Young diagram:
We denote Y(n)the set of integer partitions with size n, and Y=FnNY(n)the set of all
integer partitions. Given λY(n), a standard tableau with shape λis a numbering of the cells
of the Young diagram of λby the integers in [[1, n]] which is bijective and strictly increasing
along the rows and columns. For instance,
8
4 7
3 5
1269
is a standard tableau with shape (4,2,2,1). The set of standard tableaux with shape λwill
be denoted ST(λ), and the cardinality of this set is given by the Frame–Robinson–Thrall
hook length formula [FRT54]. Given a cell @of a Young diagram λ, its hook length h(@)is the
number of cells of the hook which is included in the Young diagram λand which contains @, the
cells above @and the cells on the right of @. For instance, the integer partition λ= (4,2,2,1)
yields the following hook lengths:
1
3 1
4 2
7521
Then, for any integer partition λY(n),
|ST(λ)|=n!
Q@λh(@);
see for instance [Mac95, Section I.4, Example 3]. In this article, we shall be interested in the
distribution of a certain statistics X: ST(λ)N, the set ST(λ)being endowed with the
uniform law. Before presenting this statistics, let us associate to the cells of a Young diagram
λanother integer: if the cell @is in i-th row and the j-th column of the Young diagram λ, its
content is c(@) = ji. For instance, λ= (4,2,2,1) admits the following contents:
3
2 1
1 0
0123
The contents are involved in numerous combinatorial formulæ in the theory of integer partitions.
For instance, the cardinality of the set SST(λ, m)of semistandard tableaux with shape λand
entries in [[1, m]] is given by the product Q@λ
m+c(@)
h(@); see [Sta99, Corollary 7.21.4]. The contents
of the cells of the Young diagrams shall also play an important role in our work.
ASYMPTOTICS OF THE MAJOR INDEX OF A RANDOM STANDARD TABLEAU 3
1.2. Major index and Schur functions. Adescent of a standard tableau of size nis an
integer i[[1, n 1]] such that i+ 1 appears in a row strictly above the row containing i. The
major index of a standard tableau Tis the sum of its descents:
maj(T) = X
iDesc(T)
i.
For instance, if λ= (4,2,2,1) and Tis the standard tableau given as an example in the previous
paragraph, then the set of descents of Tis {2,3,6,7}, and the major index is 2 +3+6 +7 = 18.
The definitions of descent and major index for a standard tableau are closely related to the
analogue definitions for a permutation. Given σS(n), a descent of the permutation σis an
index i[[1, n 1]] such that σ(i)> σ(i+ 1). For instance, the descent set of the permutation
σ= 592138647 is {2,3,6,7}. The Robinson–Schensted–Knuth algorithm yields a bijection
between S(n)and the set FλY(n)ST(λ)×ST(λ)of pairs of standard tableaux with the same
shape. For instance, 592138647 S(9) corresponds to the pair of standard tableaux
P=
9
5 8
2 6
1347
;Q=
8
4 7
3 5
1269
.
This bijection preserves the set of descents: if RSK(σ) = (P, Q), then Desc(σ) = Desc(Q); see
for instance [Loe11, Theorem 10.117].
The purpose of this article is to study the distribution of maj(T)when Tis taken uniformly at
random in the set ST(λ)of standard tableaux with shape λ, and λ=λ(n)is an integer partition
with size n,ngoing to infinity. Equivalently, this amounts to consider the distribution of maj(σ)
when σis a permutation taken uniformly at random in a RSK class of growing size. The case of
a uniform random permutation in S(n)can essentially be recovered as a particular case of our
results; see the discussion after the statement of Theorems Aand B. The following result due to
Billey–Konvalinka–Swanson [BKS20] ensures that under mild hypotheses and after appropriate
scaling, this distribution of maj(T)with T∼ U(ST(λ)) is asymptotically normal:
Theorem 1 (Billey–Konvalinka–Swanson).We denote λ0the conjugate of an integer partition
λ, which is obtained by symmetrizing the Young diagram with respect to the diagonal. Consider
a sequence of integer partitions (λ(n))n1such that
|λ(n)|=n;nλ(n)
1+;nλ(n)0
1+.
Then, with T(n)taken uniformly at random in ST(λ(n)),
maj(T(n))E[maj(T(n))]
pvar(maj(T(n))) *n+N(0,1).
The conditions nλ(n)
1+and nλ(n)0
1+are actually necessary: otherwise, the
limiting distribution exists but is not Gaussian, see [BKS20, Theorem 1.3]. We shall see in the
sequel that if |λ|=nand T∼ U(ST(λ)), then
`(λ)
X
i=1
(i1)λimaj(T)n
2
`(λ)
X
i=1 λi
2
and the variance of maj(T)is of order O(n3). Thus, in most cases, the values of maj(T)are
of order O(n2), and their fluctuations around the mean are of order O(n3
2)and asymptotically
normal. This raises the question of the large deviations of maj(T)of order O(n2): given y > 0,
what are the asymptotics of
P[maj(T(n))E[maj(T(n))] yn2] ?
4 PIERRE-LOÏC MÉLIOT AND ASHKAN NIKEGHBALI
We shall explain in this article how to estimate these probabilities if one knows the limit shape
of the partitions λ(n). On the other hand, Theorem 1ensures that
dKol maj(T(n))E[maj(T(n))]
pvar(maj(T(n))) ,N(0,1)!
= sup
sRPmaj(T(n))E[maj(T(n))] sqvar(maj(T(n)))Zs
−∞
ex2
2dx
2π
goes to 0when ngoes to infinity, but it does not give the speed of convergence, related to the
quality of the Gaussian approximation. One of our main results is a uniform upper bound for
this Kolmogorov distance, which is of order O(n1
2).
The major index of standard tableaux is related to the Schur functions and to the so-called
q-hook length formula. For any family of variables (x1, . . . , xN)with N`(λ), set
sλ(x1, . . . , xN) = det((xi)λj+Nj)1i,jN
det((xi)Nj)1i,jN
with by convention λj= 0 if j > `(λ). The specialisation xN+1 = 0 from R[x1, . . . , xN+1]to
R[x1, . . . , xN]stabilises these Schur polynomials:
N`(λ), sλ(x1, . . . , xN,0) = sλ(x1, . . . , xN).
In the projective limit in the category of graded algebras R[X] = lim
N→∞ R[x1, . . . , xN], there
exists a unique element sλ(X)whose projections are the symmetric polynomials defined above.
This is the Schur function sλ, see for instance [Mac95, Section I.3]. An important result in
the theory of these symmetric functions is the Stanley q-hook length formula [Sta99, Corollary
7.21.3]: if |q|<1, then
sλ(1, q, q2, . . . , qn, . . .) = qb(λ)Y
@λ1
1qh(@),
with b(λ) = P`(λ)
i=1 (i1)λi. Moreover, up to a combinatorial factor, the principal specialisation
sλ(1, q, q2, . . .)is the generating series of the major indices of the standard tableaux with shape
λ:
sλ(1, q, q2, . . .) =
|λ|
Y
i=1
1
1qi
X
TST(λ)
qmaj(T),
see [Sta99, Proposition 7.19.11].
1.3. Cumulants of the major index. The starting point of the argument of [BKS20] is the
following important remark, which is based on earlier works by Chen–Wang–Wang [CWW08]
and by Hwang–Zachavoras [HZ15]. Given TST(λ), set X(T) = maj(T)b(λ), and consider
the generating series of this statistics:
X
TST(λ)
qX(T)=Q|λ|
i=1(1 qi)
Q@λ(1 qh(@)).
We obtain a product of ratios of q-integers [a]q=1qa
1q. This leads to simple formulas for the
cumulants of the random variable X(T)with T∼ U(ST(λ)). Given a random variable whose
Laplace transform E[ezX ]is convergent on a disk D(0,R)={zC| |z|< R}with R > 0, we
recall that the cumulants of Xare the coefficients κ(r)(X)of the log-Laplace transform:
log E[ezX ] =
X
r=1
κ(r)(X)
r!zrin a neighborhood of 0.
ASYMPTOTICS OF THE MAJOR INDEX OF A RANDOM STANDARD TABLEAU 5
The cumulants of Xare related to its moments by a Möbius inversion formula with respect to
the lattice of set partitions:
κ(r)(X) = X
πP(r)
(1)`(π)1(`(π)1)!
`(π)
Y
j=1
E[X|πj|]
,
the sum running over the set P(r)of set partitions π1tπ2t ··· t π`(π)of the integer interval
[[1, r]]. This combinatorial formula enables one to define the cumulants of Xassuming only
that Xhas moments of all order. Now, consider a finite set Tendowed with the uniform
distribution, and a statistics X:TN. The generating function E[qX]is given by the ratio
P(q)
P(1) , where
P(q) =
X
m=0 {TT|X(T) = m}qm;P(1) =
X
m=0 {TT|X(T) = m}=|T|.
Lemma 2. Suppose that the polynomial PZ[q]is given by a ratio of q-integers:
P(q) = Ql
k=1[bk]q
Ql
k=1[ak]q
,
where {a1, . . . , al}and {b1, . . . , bl}are multisets of non-negative integers. Then, Xtakes its
values in [[0, n]] with n=Pl
k=1(bkak), and for any r1,
κ(r)(X) = Br
r
l
X
k=1
((bk)r(ak)r),
where Bris the r-th Bernoulli number. Consequently, the odd cumulants of Xof order larger
than 3vanish.
Proof. Denote cm={TT|X(T) = m}, so that P(q) = Pn
m=0 cmqm. By hypothesis, Pis
a polynomial of degree nand is the ratio of two polynomials Ql
k=1(1 qbk)and Ql
k=1(1 qak)
with degrees Pl
k=1 bkand Pl
k=1 ak, so nis equal to the difference of the two sums. Now, the
Bernoulli numbers Brare defined by their generating series
t
1et=
X
r=0
Br
tr
r!= 1 + t
t
X
r=1
Br
r
tr
r!!,
so the divided Bernoulli numbers Br
rhave for exponential generating series:
X
r=1
Br
r
tr
r!= log et1
t.
It suffices now to write, for q= ezwith zclose to 0:
log E[ezX ] =
l
X
k=1
log ezbk1
ezak1=
l
X
k=1
log ezbk1
zbklog ezak1
zak
=
X
r=1
Br
rzr l
X
k=1
((bk)r(ak)r)!.
Since t
1ett
2=tcoth( t
2)is an even function, the odd Bernoulli numbers of order 2r+ 1 3
all vanish. Therefore, κ(2r+1)(X) = 0 for any r1.
摘要:

ASYMPTOTICSOFTHEMAJORINDEXOFARANDOMSTANDARDTABLEAUPIERRE-LOÏCMÉLIOTANDASHKANNIKEGHBALIAbstract.Inthisarticle,weestablishthemod-convergenceofthemajorindexofauniformrandomstandardtableauwhoseshapeconvergesintheThomasimplex.Thisimpliesvariousprobabilisticestimates,inparticularspeedofconvergenceestimat...

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