ALMOST PERFECT LINEAR LEE CODES OF PACKING RADIUS 2ONLY EXIST FOR SMALL DIMENSIONS ZIJIAN ZHOU1AND YUE ZHOU1y_2

2025-04-30 0 0 521.6KB 29 页 10玖币
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ALMOST PERFECT LINEAR LEE CODES OF PACKING
RADIUS 2ONLY EXIST FOR SMALL DIMENSIONS
ZIJIAN ZHOU 1AND YUE ZHOU 1,
Abstract. It is conjectured by Golomb and Welch around half a century ago
that there is no perfect Lee codes Cof packing radius rin Znfor r2
and n3. Recently, Leung and the second author proved this conjec-
ture for linear Lee codes with r= 2. A natural question is whether it is
possible to classify the second best, i.e., almost perfect linear Lee codes of
packing radius 2. We show that if such codes exist in Zn, then nmust be
1,2,11,29,47,56,67,79,104,121,134 or 191.
1. Introduction
Let Vbe a metric space. A code Cof Vis just a subset of points in V. The
code Cis a perfect code with radius r, if for any point xin V, there is exactly one
point in Cwith distance at most rfrom x. Usually, perfect codes yields beautiful
mathematical structures and they also have very important applications in the
associated metric spaces.
In this paper, we are interested in perfect and almost perfect codes with respect
to the Lee metric. For other interesting topics on perfect codes, we refer to the
monograph [4] by Etzion. Let Zdenote the ring of integers. For x= (x1,· · · , xn)
and y= (y1,· · · , yn)Zn, the Lee metric (also known as `1-norm, taxicab metric,
rectilinear distance or Manhattan distance) between them is defined by
dL(x, y) =
n
X
i=1
|xiyi|for x, y Zn.
A Lee code Cis called linear, if Cis a lattice in Zn. The minimum distance d(C) of
a Lee code Ccontaining at least two elements is defined to be min{dL(x, y) : x, y
C, x 6=y}.
Lee codes have many practical applications such as interleaving schemes [2],
constrained and partial-response channels [13], and flash memory [14].
By definition, a Lee code Cis perfect if and only if
Zn=˙
[c∈C(S(n, r) + c),
where
S(n, r) := ((x1,· · · , xn)Zn:
n
X
i=1
|xi| ≤ r)
is the Lee sphere of radius rcentered at the origin and S(n, r) + c:= {v+c:
vS(n, r)}. In another word, the existence of a perfect Lee code is equivalent
Date: October 11, 2022.
Key words and phrases. Lee metric, almost perfect code, Golomb-Wech conjecture.
1
arXiv:2210.04550v1 [math.CO] 10 Oct 2022
2 Z. ZHOU AND Y. ZHOU
to a tiling of Znby Lee spheres of radius r. The cardinality of S(n, r) has been
determined in [5, 15] as follows
|S(n, r)|=
min{n,r}
X
i=0
2in
ir
i.
It is worth pointing out that a perfect linear Lee code is also equivalent to an
abelian Cayley graph of degree 2nand diameter rwhose number of vertices meets
the so-called abelian Cayley Moore bound ; see [3, 19]. For more results about the
degree-diameter problems in graph theory, we refer to the survey [11].
It has been showed by Golomb and Welch [5] that perfect Lee codes exist for
n= 1,2 and every positive integer r, and for n3 and r= 1. In the same paper,
Golomb and Welch also proposed the conjecture that there are no more perfect Lee
codes for other choices of nand r. To the best of our knowledge, this conjecture
is still far from being solved, despite many efforts and various approaches applied
on it. For more history and results about this conjecture, we refer to the survey [8]
and the references therein.
In recent years, there are some important progress on the existence of perfect
linear Lee code for small r. For r= 2, Leung and the second author [10] proved that
perfect linear Lee codes only exist for n= 1,2. For r2, Zhang and Ge [18], and
Qureshi [12] have obtained many nonexistence result by extending the symmetric
polynomial method introduced by Kim [9] for r= 2. It is worth pointing out that
by [16] the linearity assumption of a nonexistence result for perfect linear Lee codes
of radius rin Zncan be removed provided that the size of Lee sphere S(n, r) is a
prime number.
Obviously, a Lee code Cis perfect implies that the packing of Znby S(n, r) with
centers consisting of all the elements in Cis of packing density 1. As there is no
perfect linear Lee code for r= 2 and n3 by [10], one natural question is whether
the second best is possible. More precisely, one may ask the following question for
any r2.
Question 1.1. Does there exist a lattice packing of Znby S(n, r) with density
|S(n,r)|
|S(n,r)|+1 ?
If such a lattice packing exists, we call the associated linear Lee code almost
perfect. For convenience, we abbreviate the term almost perfect linear Lee code to
APLL code throughout the rest of this paper.
The packing radius (covering radius, resp.) of a Lee code Cis defined to be the
largest (smallest resp.) integer r0such that for any element wZnthere exists at
most (at least, resp.) one codeword cCwith dL(w, c)r0. It is clear that a Lee
code is perfect if and only if its packing radius and covering radius are the same.
For an APLL code with packing density |S(n,r)|
|S(n,r)|+1 , its packing radius and covering
radius are rand r+ 1, respectively.
It is easy to see that C={x(2r+2) : xZ}is the unique APLL code of packing
radius rin Zfor any r.
Let L(n, r) denote the union of n-cubes centered at each point of S(n, r) in Rn.
It is clear that each packing of Znby S(n, r) corresponds to a packing of Rnby
L(n, r). Figure 1 depicts the lattice packing of R2by L(2,2) associated with a lattice
generated by {(1,4),(3,2)}in Z2. Clearly the packing density is |S(2,2)|
|S(2,2)|+1 =13
14 .
APLL CODES OF PACKING RADIUS 2 ONLY EXIST FOR SMALL DIMENSIONS 3
Figure 1. Packing of R2by L(2,2) associated with an APLL code
Therefore this lattice is an APLL code in Z2. It is not difficult to show that the
minimum distance of an APLL code in Znis 2r+ 1 for n > 1 and 2r+ 2 for n= 1.
In [17], the following result on the nonexistence of APLL codes of packing radius
2 has been obtained.
Theorem 1.2. Let nbe a positive integer. If n0,3,4 (mod 6), then there exists
no almost perfect linear Lee code of packing radius 2.
In this paper, we consider the rest cases with n1,2,5 (mod 6). Together with
Theorem 1.2, we can prove the following result.
Theorem 1.3. There is no almost perfect linear Lee code of packing radius 2in Zn
for any positive integer nexcept for n= 1,2,11,29,47,56,67,79,104,121,134,191.
The rest part of this paper is organized as follows. In Section 2, we recall some
necessary and sufficient conditions of the existence of APLL codes of packing radius
2 in terms of group ring equations. In Section 3, we recall how to prove Theorem
1.2 in [17] and provide an outline of the proof of Theorem 1.3. As this proof is
very long, we separate it into several lemmas and theorems in Sections 4–7, which
tell us that nis bounded if there exist APLL codes of packing radius 2 in Znfor
n1,2,5 (mod 6). In Section 8, by two nonexistence results from [6] and [7], we
can exclude most of the rest small values of nand finish the proof of Theorem 1.3.
In Section 9, we conclude this paper with a conjecture and several remarks.
2. Preliminaries
Let Gbe a finite group. Let Z[G] denote the set of formal sums PgGagg, where
agZand Gis a finite multiplicative group. The addition and the multiplication
on Z[G] are defined by
X
gG
agg+X
gG
bgg:= X
gG
(ag+bg)g,
and
(X
gG
agg)·(X
gG
bgg) := X
gG
(X
hG
ahbh1g)·g,
4 Z. ZHOU AND Y. ZHOU
for PgGagg, PgGbggZ[G]. Moreover,
λ·(X
gG
agg) := X
gG
(λag)g
for λZand PgGaggZ[G].
For an element A=PgGaggZ[G] and tZ, we define
A(t):= X
gG
aggt.
A multi-subset Dof Gcan be viewed as an element PgDgZ[G]. In the rest of
this paper, by abuse of notation, we will use the same symbol to denote a multi-
subset in Gand the associated element in Z[G]. Moreover, |D|denotes the number
of distinct elements in D. In another word, |D|is the cardinality of the support of
Dwhich is defined by Supp(D) := {gG: the coefficient of gin Dis positive}.
In [17, Section 3], Xu and the second author have proved the equivalence between
the existence of an APLL code of packing radius 2 and some group ring equations.
Lemma 2.1. There exists an APLL code of packing radius 2in Znif and only if
there is an abelian group Hof order n2+n+1 containing two inverse-closed subsets
T0and T1such that the identity element eT0, and the following two group ring
equations in Z[H]holds.
T0T1=He,(1)
T2
0+T2
1= 2HT(2)
0T(2)
1+ 2ne.(2)
Example 2.2. The following examples of T0and T1satisfy (1) and (2).
(a) For n= 1,H=hhi
=C3. Let T0={e}and T1={h, h2}.
(b) For n= 2,H=hhi
=C7. Define
T0={e, h, h6}and T1={h2, h5}.
The following result is a collection of necessary conditions for T0and T1, which
is also proved in [17].
Lemma 2.3. Let Hbe an abelian group of order n2+n+ 1. Suppose T0, T1are
subsets of Hsatisfying eT0,T(1)
i=Tifor i= 0,1,(1) and (2). Then the
following statements hold.
(a) eT0,e /T1;
(b) T0T1=and T(2)
0T(2)
1=;
(c) T0(T(2)
0\ {e}) = T0T(2)
1=;
(d) {ab :a6=b, a, b T0} ∩ T(2)
0={e};
(e) When nis odd, |T0|=nand |T1|=n+ 1;
(f) When nis even, |T0|=n+ 1 and |T1|=n;
(g) There is no common non-identity element in T2
0and T2
1;
(h) T0T(3)
0={e}.
3. Outline of the method
First, let us take a look at the sketch of the proof of the nonexistence of APLL
codes of packing radius 2 with n0,3,4 (mod 6) in [17].
APLL CODES OF PACKING RADIUS 2 ONLY EXIST FOR SMALL DIMENSIONS 5
By Lemma 2.1, we only have to show there is no T0and T1in Hsatisfying the
necessary and sufficient conditions in it. Define ˆ
T=T0+T1Z[H], k0=|T0|and
k1=|T1|.
Multiplying T0and T1on both sides of (2), we get
T3
0= (2k0k1)H+ 2nT0+T1T0ˆ
T(2) ,(3)
T3
1= (2k1k0)H+ 2nT1+T0T1ˆ
T(2) .(4)
Consider the above two equations modulo 3
ˆ
T(2)T0(2k0k1)H+T1T(3)
0+ 2nT0(mod 3),
ˆ
T(2)T1(2k1k0)H+T0T(3)
1+ 2nT1(mod 3).
Note that T3
iT(3)
i(mod 3) for i= 0,1. If 3 -|H|, then T(3)
0and T(3)
1are both
subsets of H; for 3 | |H|, we can also show that there are at most 2 elements in
T(3)
iappearing twice for i= 0,1; see Lemma 4.1. Hence, by calculation, we can
derive some strong restrictions on the coefficients of most of the elements in the
right-hand side of the above two equations. For instance, when n1 (mod 3) and
nis odd, the first equation becomes
ˆ
T(2)T0T1T(3)
0+ 2T0(mod 3).
As T1,T(3)
0and T0are approximately of size n, most of the elements in Happear
in ˆ
T(2)T0for 3ktimes, k= 0,1,· · · .
Let Xi(Yi, resp.) be the subset of elements of Happearing in ˆ
T(2)T0(ˆ
T(2)T1,
resp.) exactly itimes for i= 0,1,· · · , M0(M1, resp.), which means Xi’s (Yi’s,
resp.) form a partition of the group H. In particular, we define M0and M1to be
the largest integers such that XM0and YM1are non-empty sets. Then
ˆ
T(2)T0=
M0
X
i=0
iXi,(5)
ˆ
T(2)T1=
M1
X
i=0
iYi.(6)
By (5) and (6), we have the following three conditions on the value of |Xi|’s and
|Yi|’s:
M0
X
i=1
i|Xi|= (2n+ 1)k0,(7)
M1
X
i=1
i|Yi|= (2n+ 1)k1,(8)
M0
X
i=0
|Xi|=
M1
X
i=0
|Yi|=n2+n+ 1.(9)
摘要:

ALMOSTPERFECTLINEARLEECODESOFPACKINGRADIUS2ONLYEXISTFORSMALLDIMENSIONSZIJIANZHOU1ANDYUEZHOU1,yAbstract.ItisconjecturedbyGolombandWelcharoundhalfacenturyagothatthereisnoperfectLeecodesCofpackingradiusrinZnforr2andn3.Recently,Leungandthesecondauthorprovedthisconjec-tureforlinearLeecodeswithr=2.Anatu...

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