
3
For definiteness, we consider below the rotation around
the zaxis, which can be written in the cylindrical coordi-
nates as follows: (ρ, ϕ, z, τ )→(ρ, ϕ −ΩIτ, z, τ +β). The
boundary conditions (8) are visualized in Fig. 1. The
imaginary rotation in the whole spacetime does not lead
to causality problems [4] and can be formulated in the
thermodynamic limit in the whole Euclidean space [8].
The free energy of bosonic and fermionic systems under
the imaginary rotation are straightforwardly obtained by
identifying the angular frequencies (4) in the free energy
in the co-rotating frame (1) and (2), respectively.
Below we consider free gases of bosonic and fermionic
particles subjected to imaginary rotation. The latter is
formulated in terms of the boundary condition (8) in the
imaginary time formalism. In the thermodynamic limit,
these gases possess a fractal structure in their thermo-
dynamic properties and host exotic excitations with oc-
cupation numbers different from those for bosons and
fermions.
B. Fractal thermodynamics of imaginary rotation
1. Hints from classical bosonic solutions
Analysis of classical solutions in Yang-Mills theory
has shown that the imaginary rotation with the rational
nonzero values of the angular frequency (5) corresponds
to the thermal bath with uniform temperature [9]:
T=1
qβ for ΩIβ
2π≡χ
2π=p
q,(9)
where βis the length of the lattice in the imaginary-
time direction and the rational number p/q, with positive
integers p, q = 1,2, . . . , represents an irreducible fraction.
Equation (9) provides us with two hints on the be-
havior of systems under imaginary rotation. First, it
suggests that temperature changes in a non-analytical
way2with the imaginary frequency ΩIthus forbidding
the analytical continuation from imaginary to real-valued
angular frequencies. Second, it stresses the significance
of rational numbers which is particular for fractal struc-
tures [16]. Thus, Eq. (9) provides us with a signature of a
fractal behavior of imaginary rotation, which we explore
further below.
2. Free bosons at imaginary rotation
Let us now consider free bosons in thermal equilibrium
in the thermodynamic limit. In the cylindrical coordi-
nates, the Hamiltonian for a scalar particle possesses the
2For example, two close values of the imaginary frequency,
ΩIβ/(2π)=1/2 and 999/2000, correspond, respectively, to the
temperature values (9) T= 1/(2β) and T= 1/(2000β) that differ
from each other by three orders of magnitude.
following eigenfunctions,
φkρ,kz,m(ρ, z, ϕ) = N1eimϕeikzzJm(kρρ),(10)
where Jmis the Bessel function and N1is a normalization
factor. The corresponding energy eigenvalues are
ωkρ,kz=qk2
ρ+k2
z+M2,(11)
where kρ>0 and kz∈Rare the momenta along the
radial direction ρand the zaxis, respectively. The pro-
jection of the angular momentum on the zaxis, m∈Z,
does not enter the expression for the eigenenergy (11)
thus corresponding to a degeneracy factor of the eigen-
states. The integration measure in Eq. (1) takes the form:
X
Z
α,m
≡Z∞
0
kρdkρ
2πZ∞
−∞
dkz
2πX
m∈Z
.(12)
For the rational angular momentum ΩIβ/(2π) = p/q,
we combine the elements of the sum over the angular
quantum number min Eq. (12) in the groups of q:
X
m∈Z
f(m) = X
m∈Z
q−1
X
a=0
f(qm+a), q = 1,2, . . . .(13)
Then the bosonic partition function (1) at the imaginary
angular frequency (4) can be identically rewritten as
F(b)
β=V
βZ∞
0
kρdkρ
2πZ∞
−∞
dkz
2πX
m∈ZX
r=±1
×ln 1−e−qβ(ωkρ,kz−rµ).(14)
where we have used the identity (taking γ > 0):
1
2X
c=±1
q−1
X
m=0
ln 1−e−γ+2πicm p
q= ln 1−e−qγ .(15)
Due to the degeneracy of the energy eigenvalues (11) with
respect to the angular momentum m, this identity can be
applied to Eq. (14). Special care is needed to match the
infinite sums over mand mwhich require a regulariza-
tion. Introducing the ultraviolet regulator in Eq. (13),
e−|m|with > 0, one finds in the limit →0 that the
sums over mand mare not equivalent but differ by the
factor of 1/q, implying Pm∈Z= (1/q)Pm∈Z.
Thus, free bosonic gas subjected to the rational imag-
inary angular frequency (9) at temperature Tin the ab-
sence of background potential has the same free energy as
the non-rotating gas at lower temperature T/q ≡1/(qβ):
F(b)
βΩI=2π
β
p
q
=F(b)
qβ Ω=0
.(16)
This relation complies with Eq. (9) obtained for classical
bosonic solutions. Notice that Eq. (16) does not depend
on the numerator pof the irreducible fraction p/q.
The equivalence (16) is easy to understand. The ro-
tation with the angular frequency ΩI=2π
β
p
qrotates the