Generation of measures on the torus with good sequences of integers

2025-04-22 0 0 592.1KB 44 页 10玖币
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Generation of measures on the torus with good sequences
of integers
E. Lesigne, A. Quas, J. Rosenblatt, M. Wierdl
November 14, 2023
Let S:= (s1<s2<. . . )be a strictly increasing sequence of positive inte-
gers and denote e(β):=e2πiβ. We say Sis good if for every real αthe limit
limN1
NnNe(snα)exists. By the Riesz representation theorem, a se-
quence Sis good iff for every real αthe sequence (snα)possesses an asymp-
totic distribution modulo 1. Another characterization of a good sequence
follows from the spectral theorem: the sequence Sis good iff in any proba-
bility measure preserving system (X,m,T)the limit limN1
NnNf(Tsnx)
exists in L2-norm for fL2(X).
Of these three characterization of a good set, the one about limit mea-
sures is the most suitable for us, and we are interested in finding out what
the limit measure µS,α:=limN1
NnNδsnαon the torus can be. In this
first paper on the subject, we investigate the case of a single irrational α. We
show that if Sis a good set then for every irrational αthe limit measure µS,α
must be a continuous Borel probability measure. Using random methods,
we show that the limit measure µS,αcan be any measure which is absolutely
continuous with respect to the Haar-Lebesgue probability measure on the
torus. On the other hand, if νis the uniform probability measure supported
on the Cantor set, there are some irrational αso that for no good sequence
Scan we have the limit measure µS,αequal ν. We leave open the question
whether for any continuous Borel probability measure νon the torus there
is an irrational αand a good sequence Sso that µS,α=ν.
Contents
1Introduction, main results 2
1.1 Good sequences, main question 2
1.2 Main results 4
1.3 Weighted averages 8
1.4 Applications in ergodic theory 10
1.5 Future work 10
1.6 Summary of notation 11
2Basic example for representation 11
3Proof of theorem 7.1 for indicators 14
4Measures that cannot be represented at every irrational α23
4.1 Proof of theorem 5.3 24
4.2 Proof of theorem 6.1 24
arXiv:2210.02233v2 [math.CA] 12 Nov 2023
GENERATION OF MEASURES ON THE TORUS WITH GOOD SEQUENCES OF INTEGERS 2
5Representing by weights 25
6Proof of theorem 7.1 for bounded ρ27
6.1 Notes to lemma 28.1 31
7Absolute continuity and positive mean 31
7.1 Proof of theorem 7.2 (b) 31
7.2 Proof of theorem 9.3 (b) 32
8Proof of theorem 7.1 for unbounded ρ33
9The limit measure at rational points 38
10 Examples 39
10.1 Two good sets, but their intersection has no mean. 39
10.2 R1R2and R1R2have means but are not good 40
10.3 Open set Uwith visit set {n:nαU}not good 41
References 43
1 Introduction, main results
Throughout the paper we will use the arithmetic average operator A: for a
finite index set S, a vector space Vand a SVfunction fwe define
ASf(s)
ASf(s) = AsSf(s):=1
#S
sS
f(s)(2.1)
where #Sdenotes the number of elements in S.
We use the convention that if an interval appears as an index set in
a summation then we consider only the integers in the interval. For
example, n[0,N)an=n∈{0,1,...,N1}an.
We also use Weyl’s notation e(β):=e2πiβ. Note that ep(β) = e(pβ)
for every integer p.
We denote by Tthe torus R/Zand we represent it as the unit closed
interval [0, 1]with 0=1.
1.1 Good sequences, main question
2.1 Definition Good sequence
We say that a sequence S= (sn)nNof integers is good if the limit
limNAn[1,N]e(snα)exists for every real number α.
Good sequences have been extensively studied in many parts of mathe-
matics, such as in number theory and ergodic theory.
GENERATION OF MEASURES ON THE TORUS WITH GOOD SEQUENCES OF INTEGERS 3
In this paper we restrict our attention to strictly increasing sequences S
of positive integers in which case we can and will consider Sas a subset of
N, and we’ll use the concept of good sequence and good set interchange-
ably.
Among the wellknown good sequences are the full set Nof positive
integers1, the sequence (n2)nNof squares2and the sequence (pn)nNof 1Weyl 1916.
2Weyl 1916.
primes3where pndenotes the nth prime number. For these sequences the
3Vinogradow 1937.
limits limNAn[1,N]e(snα)are as follows
lim
N
An[0,N)e(nα) = (1if α=1
0if α̸=0
lim
N
An[0,N)e(n2α) =
Ab[1,q]eb2a
qif α=a
q,gcd(a,q) = 1
0if αis irrational
lim
N
An[1,N]e(pnα) =
Ab[1,q]
gcd(b,q)=1
e(b/q)if α=a
q,gcd(a,q) = 1
0if αis irrational
(3.1)
In case of a good sequence S= (sn)and a fixed α, the existence of
limNAn[1,N]e(snpα)for every pZimplies, by uniform approxima-
tion of a continuous TCfunction by trigonometric polynomials, that
for every continuous TCfunction ϕthe limit limNAn[1,N]ϕ(snα)
exists. By the Riesz representation theorem, this implies that the weak
limit limNAn[1,N]δsnαof discrete measures An[1,N]δsnαon Texists.
By this argument, the existence of limNAn[1,N]e(snα)for every α
implies the existence of the limit measure limNAn[1,N]δsnαfor every α.
Denote the Haar-Lebesgue probability measure on the torus Tby λand
recall that the Fourier coefficients λ(ep)of λsatisfy
λ(ep) = (1for p=0
0for pZ,p̸=0(3.2)
where for a given measure νand ν-integrable function ϕ, we use4the 4and will use troughout the paper
functional notation ν(ϕ)for the integral of ϕwith respect to ν,
ν(ϕ) = Zϕdν(3.3)
GENERATION OF MEASURES ON THE TORUS WITH GOOD SEQUENCES OF INTEGERS 4
For our three good sets the limit measures are as follows.
lim
N
An[1,N]δnα=(Ab[1,q]δb/qif α=a/q,gcd(a,q) = 1
λif αis irrational
lim
N
An[1,N]δn2α=
Ab[1,q]δb2a
qif α=a
q,gcd(a,q) = 1
λif αis irrational
lim
N
An[1,N]δpnα=
Ab[1,q]
gcd(b,q)=1
δb/qif α=a
q,gcd(a,q) = 1
λif αis irrational
(4.1)
What we see in these three examples is that in case of irrational αthe
limit measure is the Haar-Lebesgue measure λand in case of rational
α=a/q,gcd(a,q) = 1, the limit measure is supported on a subset of the
qth roots of unity and appears to be quite uniform on its support. In case
of irrational α, the simplest question is if it’s possible that the limit measure
is not λ. In case of rational α, we can ask if the limit measure always has
to show some kind of uniformity.
Let us consider a good sequence S= (sn). The existence of the limit
limNAn[1,N]e(snα)for every αimplies that the weak limit limNAn[1,N]δsnα
of discrete measures An[1,N]δsnαon Texists for every α. Let us denote
this weak limit measure by µS,α,
µS,α:=lim
N
An[1,N]δsnα(4.2)
The main question we want to investigate in this paper is
4.1 Question Main question
What can the limit measure µS,αbe? Can it be any Borel probability
measure on T?
1.2 Main results
As we stated earlier, we try to answer question 4.1 for strictly increasing
sequences, and unless we say otherwise, we assume from now on that
S= (sn)is a strictly increasing sequence of positive integers which we
often consider as a subset of N.
Our first observation is that the answer to question 4.1 will depend on
α. If αis a rational number, say, α=a
qwith gcd(a,q) = 1, then the limit
measure is clearly supported on the set
Tq:={b/q:b[1, q]}(4.3)
of qth roots of unity. So the question is if the limit measure µS,a/qcan
be any probability measure supported on Tq? The answer is yes. First a
terminology.
GENERATION OF MEASURES ON THE TORUS WITH GOOD SEQUENCES OF INTEGERS 5
5.1 Definition Representable measure at α
Let Sbe a good set, and let νbe a nonzero, finite Borel measure on T.
We say that Srepresents νat αTif µS,α=1
ν(T)ν.
We say νis representable at αif there is a good set which represents νat
α.
5.2 Theorem Every probability measure on Tqcan be represented
Let qand abe positive integers with gcd(a,q) = 1, and let νbe a
probability measure supported on the set Tqof qth roots of unity.
Then νcan be represented at a
q, that is, there is a good set Sso that
µS,a
q=ν.
Before discussing the limit measure µS,αfor irrational α, let us note the
following fact which will help us appreciate the concept of a good set.
Suppose we are given an irrational number αTand a Borel prob-
ability measure νon T. We claim that there exists a sequence (xn)in T
with asymptotic distribution ν, i. e. such that limNAn[1,N]δxn=ν.
Considering such a sequence and using the density of the sequence (nα)n
in T, we can select a strictly increasing sequence (sn)of integers so that
limn(snαxn) = 0 mod 1, and we have limNAn[1,N]δsnα=ν. Taking
S={sn:nN}, we could say that µS,α=ν, but nothing insures us
that the set Sis good.
There are different ways to prove the preceding claim. For example
we can pick the numbers xnrandomly and independently with law ν, and
the strong law of large numbers asserts that the sequence (xn)has, almost
surely, the right asymptotic distribution.
It is particularly simple to get a point-mass as a limit measure. For
example, to get the Dirac measure at 1/2, so ν=δ1/2, take a strictly
increasing sequence (sn)of natural numbers so that snαconverges to 1/2
mod 1, and let S:={sn:nN}. In contrast to this example, for good
sets we have a dramatic departure from the case of rational α.
5.3 Theorem µS,αis continuous for irrational α
Only continuous measures can be represented at an irrational number.
To spell this out, let S= (sn)be a good sequence and αbe an irrational
number.
Then the limit Borel probability measure µS,α=limNAn[1,N]δsnαis a
continuous measure.
The obvious question in turn is if any given continuous Borel proba-
bility measure can be represented at any irrational number. The answer is
no, as the next result shows.
摘要:

GenerationofmeasuresonthetoruswithgoodsequencesofintegersE.Lesigne,A.Quas,J.Rosenblatt,M.WierdlNovember14,2023LetS:=(s1

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